Question

A school paid $248 for new basketballs and soccer balls. The number of basketballs purchased was 6 less than 3 times the number of soccer balls purchased. Basketballs cost $28 each and soccer balls cost $20 each. How many total balls did the school purchase?

Answer 1

4 Soccer balls and 6 Basketballs

Explanation:

You can solve this problem by setting up a system of equations. Letting x be Soccer balls and y be Basketballs. Remember, Money goes with, Money goes with Money, meaning that for this problem the first equation that can be made is $248 = $28y + $20x with Y being basketballs and x being soccerballs. Next is a little more difficult. You will be creating the equation y=3x-6 because it is 6 less than 3 times the amount of x or Soccer balls. From here you can plug in the equations into a graphing calculator and graph it and see where the two lines intersect. This would be at (4, 6). When I said to let x equal Soccer Balls and y equal basketballs that is where I got the 4 soccer balls and 6 basketballs.