304,660 views
8 votes
8 votes
What is the period of the function y=tan (4/pi (x-pi/3))

O 3 units
O4 units
O 6 units
O 8 units

What is the period of the function y=tan (4/pi (x-pi/3)) O 3 units O4 units O 6 units-example-1
User Norbekoff
by
2.9k points

2 Answers

23 votes
23 votes

Answer: 4 units

Explanation:

User Tony Dong
by
2.6k points
13 votes
13 votes

Answer:

Period = 4 units

Explanation:

Standard form of a tangent function:


f(x)=\sf A \tan(B(x+C))+D

  • A = vertical stretch
  • π / |B| = period (distance between any two consecutive vertical asymptotes)
  • C = phase shift (horizontal shift - positive is to the left)
  • D = vertical shift

The tangent function has a vertical asymptote whenever cos(x) = 0

The tangent function does not have an amplitude because it has no maximum or minimum value.

Given function:


y=\tan \left((\pi)/(4)\left(x-(\pi)/(3)\right)\right)

Therefore:

  • Vertical stretch (A) = none

  • \textsf{Period}=(\pi)/(\left|(\pi)/(4)\right|)=4
  • Phase shift (C) = π/3 to the right
  • Vertical shift = none
User HoppyKamper
by
3.3k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.