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find the zeros of following quadratic polynomial and verify the relationship between the zeros and the coefficient of the polynomial f(x)=5x-4√3+2√3x²​

2 Answers

3 votes

Answer:

Explanation:

Rewrite the given polynomial in the form ax² + bx + c:

To find the zeros, set the function to zero and solve for x using the quadratic formula.

Quadratic formula:

Therefore,

a = 2√3

b = 5

c = - 4√3

Substituting the values into the quadratic formula:

The sum of the roots of a polynomial is -b/a:

The sum of the found roots is:

Hence proving the sum of the roots is -b/a

The product of the roots of a polynomial is: c/a

The product of the found roots is:

Hence proving the product of the roots is c/a

Therefore, the relationship between the roots and the coefficients is verified.

User Tarun Behal
by
4.8k points
10 votes

Answer:


\textsf{Zeros}: \quad x=\frac {√(3)}{2}, \:\:x=-\frac {4√(3)}{3}

Explanation:

Rewrite the given polynomial in the form ax² + bx + c:


f(x)=2 √(3)x^2+5x-4 √(3)

To find the zeros, set the function to zero and solve for x using the quadratic formula.


\implies 2 √(3)x^2+5x-4 √(3)=0

Quadratic formula:


x=(-b \pm √(b^2-4ac) )/(2a)\quad\textsf{when }\:ax^2+bx+c=0

Therefore,

  • a = 2√3
  • b = 5
  • c = - 4√3

Substituting the values into the quadratic formula:


\implies x=\frac{-5 \pm \sqrt{5^2-4(2√(3))(-4√(3))} }{2(2√(3))}


\implies x=\frac {-5 \pm \sqrt {121}}{4√(3)}


\implies x=\frac {-5 \pm 11}{4√(3)}


\implies x=\frac {6}{4√(3)}, \:\:x=\frac {-16}{4√(3)}


\implies x=\frac {3}{2√(3)}, \:\:x=-\frac {4}{√(3)}


\implies x=\frac {√(3)}{2}, \:\:x=-\frac {4√(3)}{3}

The sum of the roots of a polynomial is -b/a:


\implies -(b)/(a)=-(5)/(2 √(3))=-(5√(3))/(6)

The sum of the found roots is:


\implies \left(\frac {√(3)}{2}\right)+\left(-\frac {4√(3)}{3}\right)=-(5√(3))/(6)

Hence proving the sum of the roots is -b/a

The product of the roots of a polynomial is: c/a


\implies (c)/(a)=(-4√(3))/(2√(3))=-2

The product of the found roots is:


\implies \left(\frac {√(3)}{2}\right)\left(-\frac {4√(3)}{3}\right)=-(12)/(6)=-2

Hence proving the product of the roots is c/a

Therefore, the relationship between the roots and the coefficients is verified.

User Attmik
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4.9k points