Question

What is the value of tan(alpha), if CH=3, BH=6.4

Answer 1

`\\ \tt\longmapsto CH^2=AH(BH)`

`\\ \tt\longmapsto 9=6.4AH`

`\\ \tt\longmapsto AH=1.4`

So

`\\ \tt\longmapsto tan\alpha=CH/AH`

`\\ \tt\longmapsto tan\alpha =(3)/(1.4)`

`\\ \tt\longmapsto tan\alpha=2.14`

Answer 2

• 6.4 / 3 or 2.13

Explanation:

• tangent = opposite / adjacent
• tan α = CH/AH

The triangles ACH and CBH are similar by AA.

According to similarity we have same ratio of corresponding sides:

• CH/AH = BH/CH

So the value of the tan α is:

• tan α = BH/CH = 6.4 / 3 ≈ 2.13