Instructions: Find the missing side lengths. Leave your answers as radicals in simplest form.

Question

asked Jul 17, 2021 182k views

1 Answer

Isdal · Answer 1 · 2021-07-23T06:17:08+0000

Given:

A figure.

To find:

The values of x and y.

Solution:

We know that, in a right angled triangle,

$\sin \theta =(Perpendicular)/(Hypotenuse)$

$\sin 60^\circ =(x)/(16)$

(√(3))/(2) =(x)/(16)

Multiply both sides by 16.

(√(3))/(2)* 16=(x)/(16)* 16

8√(3)=x

And,

$\cos \theta =(Base)/(Hypotenuse)$

$\cos 60^\circ =(y)/(16)$

(1)/(2)=(y)/(16)

Multiply both sides by 16.

(16)/(2)=y

8=y

Therefore, the missing side lengths are
and
.