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Question 10 of 32

A sample of 2 mol of diatomic gas is measured to have a temperature of 323
K. If the mass of the gas is 0.032 kg, what is the approximate average speed
of the molecules in the gas? (Recall that the equation for kinetic energy due
1
3
to translation in a gas is KEtranslational=mv²=nRT, and R= 8.31 J/(mol-
K).)
2
2

User Rlib
by
2.4k points

1 Answer

20 votes
20 votes

Final answer:

The approximate average speed of the gas molecules is approximately 533 m/s.

Step-by-step explanation:

The average speed of gas molecules can be calculated using the equation:

v = sqrt((3kT)/(m))

Where v is the average speed, k is the Boltzmann constant, T is the temperature in Kelvin, and m is the mass of the molecules. Substituting the given values into the equation:

v = sqrt((3 * 8.314 * 323) / (0.032 * 2))

The approximate average speed of the gas molecules is approximately 533 m/s.

User Jacob Schoen
by
3.3k points