10.4k views
0 votes
A boulder with a mass of 2,500 kg resting on a ledge 200 m above the ground falls. If the boulder’s ME is conserved, what is the speed of the boulder just before it hits the ground?

User Groner
by
6.3k points

1 Answer

6 votes

Answer:

nitial GPE = final KE 2500*10*200 = ½ 2500*v^2 v^2 = 2*10*200 v= 63.24 m/sec

Step-by-step explanation:

User Nkrkv
by
6.0k points