Complete Question
The diagram for this question is shown on the first uploaded image
Answer:
The value is
![F_j = 550\ N](https://img.qammunity.org/2021/formulas/physics/college/qsxxbnk8m0og1o3x3frouz0r4hqfth40bm.png)
Step-by-step explanation:
From the question we are told that
The length of the stretcher is
![d = 2.0 \ m](https://img.qammunity.org/2021/formulas/physics/college/f9bdlf4gtabsb78mtkoaxom8227ifqpl5r.png)
The weight of the stretcher is
![W = 100 \ N](https://img.qammunity.org/2021/formulas/physics/college/bpbcox3aynj6i30xta10yba7nreqzbu7i2.png)
The weight for Wayne is
![W_w = 800 \ N](https://img.qammunity.org/2021/formulas/physics/college/cfk1y9gamtorjgfk6uo6ddi6qs2i5momqf.png)
The distance of center of gravity for Wayne from Chris is
![c_w = 75 cm = 0.75 \ m](https://img.qammunity.org/2021/formulas/physics/college/9o5tg4hx8ptbcic2qs0483ybk20u5j2bmi.png)
Generally taking moment about the first end where Chris is
=> upward moment
Here
is the force applied by Jamie
Generally taking moment about the second end where Jamie is
=> downward moment
Generally at equilibrium , the upward moment is equal to the downward moment
![F_j * d = W * ( (d)/(2) ) + W_w * (d - c_w)](https://img.qammunity.org/2021/formulas/physics/college/x9tvnzoi9ao2mfg2b674bnf33x2y8v9yga.png)
=>
![F_j * 2 = 100 * ( ( 2)/(2) ) + 800 * (2 - 0.75)](https://img.qammunity.org/2021/formulas/physics/college/5aj2t0cq7l1qn4ni6ithwnw2g35wauyx9y.png)
=>
![F_j = 550\ N](https://img.qammunity.org/2021/formulas/physics/college/qsxxbnk8m0og1o3x3frouz0r4hqfth40bm.png)