Question

PLZ ONLY ANSWER IF U CAN SHOW STEP BY STEP! Susanna is packaging a blend of mixed nuts and candies for wedding favors. The mixed nuts cost her $3 per pound and the candies cost her $4 per poun d. Susanna bought a total of 8 lbs of nuts and candies and spent a total of $27. How many pounds of nuts and candies did Susanna buy? – Include specific steps in your letter

Answer 1

By using the elimination method to solve the system of equations derived from the given information, we find that Susanna bought 5 pounds of nuts and 3 pounds of candies for the wedding favors.

Step-by-step explanation:

Steps to Calculate Pounds of Nuts and Candies

Let's denote the pounds of nuts as N and the pounds of candies as C. The given information allows us to set up two equations:

1. N + C = 8 (Total weight equation)
2. 3N + 4C = 27 (Total cost equation)

To solve these equations, we can use the method of substitution or elimination. We'll use the elimination method:

1. Multiply the first equation by 3, the cost per pound of nuts, to make the coefficients of N the same:

• 3N + 3C = 24

Now subtract the new equation from the cost equation:

• (3N + 4C = 27) - (3N + 3C = 24)
• This gives us C = 3

Substitute the value of C back into the total weight equation:

• N + 3 = 8
• This gives us N = 5

Susanna bought 5 pounds of nuts and 3 pounds of candies.

Answer 2

Susanna bought 3 pounds of candies and 5 pounds of mixed nuts

Step-by-step explanation:

Represent Nuts with N and Candies with C

For Amount:

`3N + 4C = 27`

For Weights:

`N + C =8`

Required

Solve for N and C

Make N the subject in the second equation

`N=8 - C`

Substitute 8 - C for N in the first equation.

`3N + 4C = 27`

`3(8 - C) + 4C = 27`

`24 - 3C + 4C = 27`

`24 + C = 27`

Solve for C

`C = 27 - 24`

`C =3`

Recall that:

`N=8 - C`

`N = 8 - 3`

`N = 5`

Hence, Susanna bought 3 pounds of candies and 5 pounds of mixed nuts