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PLZ ONLY ANSWER IF U CAN SHOW STEP BY STEP! Susanna is packaging a blend of mixed nuts and candies for wedding favors. The mixed nuts cost her $3 per pound and the candies cost her $4 per poun d. Susanna bought a total of 8 lbs of nuts and candies and spent a total of $27. How many pounds of nuts and candies did Susanna buy? – Include specific steps in your letter

User Sangsoo
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7 votes

Final answer:

By using the elimination method to solve the system of equations derived from the given information, we find that Susanna bought 5 pounds of nuts and 3 pounds of candies for the wedding favors.

Step-by-step explanation:

Steps to Calculate Pounds of Nuts and Candies

Let's denote the pounds of nuts as N and the pounds of candies as C. The given information allows us to set up two equations:

  1. N + C = 8 (Total weight equation)
  2. 3N + 4C = 27 (Total cost equation)

To solve these equations, we can use the method of substitution or elimination. We'll use the elimination method:

  1. Multiply the first equation by 3, the cost per pound of nuts, to make the coefficients of N the same:
  • 3N + 3C = 24
Now subtract the new equation from the cost equation:
  • (3N + 4C = 27) - (3N + 3C = 24)
  • This gives us C = 3
Substitute the value of C back into the total weight equation:
  • N + 3 = 8
  • This gives us N = 5

Susanna bought 5 pounds of nuts and 3 pounds of candies.

User Sudeep Juvekar
by
7.8k points
2 votes

Answer:

Susanna bought 3 pounds of candies and 5 pounds of mixed nuts

Step-by-step explanation:

Represent Nuts with N and Candies with C

For Amount:


3N + 4C = 27

For Weights:


N + C =8

Required

Solve for N and C

Make N the subject in the second equation


N=8 - C

Substitute 8 - C for N in the first equation.


3N + 4C = 27


3(8 - C) + 4C = 27


24 - 3C + 4C = 27


24 + C = 27

Solve for C


C = 27 - 24


C =3

Recall that:


N=8 - C


N = 8 - 3


N = 5

Hence, Susanna bought 3 pounds of candies and 5 pounds of mixed nuts

User Lonesomeday
by
7.9k points
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