What is the solution of the equation when solved using the quadratic formula?x^(2) +20=0

Question

What is the solution of the equation when solved using the quadratic formula?
`x^(2) +20=0`

Answer 1

`x=\pm2i√(5)`

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Algebra I

• Standard Form: ax² + bx + c = 0
• Quadratic Formula:
  `x=(-b\pm√(b^2-4ac) )/(2a)`

Algebra II

• Imaginary Numbers: √-1 = i

Explanation:

Step 1: Define Equation

x² + 20 = 0

Step 2: Identify Variables

a = 1

b = 0

c = 20

Step 3: Find roots x

1. Substitute:
   `x=(-0\pm√(0^2-4(1)(20)) )/(2(1))`
2. Exponents:
   `x=(-0\pm√(0-4(1)(20)) )/(2(1))`
3. Multiply:
   `x=(-0\pm√(0-80) )/(2)`
4. Subtract:
   `x=(\pm√(-80) )/(2)`
5. Factor:
   `x=(\pm√(-1) √(80) )/(2)`
6. Simplify:
   `x=(\pm4i√(5) )/(2)`
7. Divide:
   `x=\pm2i√(5)`