Question

\frac { 6 ^ { n + 2 } - 6 ^ { n } } { 6 ^ { n + 1 } + 6 ^ { n } }

Solve this ...
this is the question of laws of indices(exponent)​

Answer 1

Answer: 5

Work Shown:

`m = (6^(n+2)-6^(n))/(6^(n+1)+6^(n))\\\\m = (6^(n)*6^2-6^(n))/(6^(n)*6^1+6^(n))\\\\m = (6^(n)*36-6^(n))/(6^(n)*6+6^(n))\\\\m = (6^(n)(36-1))/(6^(n)(6+1))\\\\m = (6^(n)(35))/(6^(n)(7))\\\\m = (35)/(7)\\\\m = 5\\\\`

Therefore,

`(6^(n+2)-6^(n))/(6^(n+1)+6^(n))=5\\\\`