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10 votes
10 votes
\frac { 6 ^ { n + 2 } - 6 ^ { n } } { 6 ^ { n + 1 } + 6 ^ { n } }

Solve this ...
this is the question of laws of indices(exponent)​

User Woxingxiao
by
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1 Answer

22 votes
22 votes

Answer: 5

Work Shown:


m = (6^(n+2)-6^(n))/(6^(n+1)+6^(n))\\\\m = (6^(n)*6^2-6^(n))/(6^(n)*6^1+6^(n))\\\\m = (6^(n)*36-6^(n))/(6^(n)*6+6^(n))\\\\m = (6^(n)(36-1))/(6^(n)(6+1))\\\\m = (6^(n)(35))/(6^(n)(7))\\\\m = (35)/(7)\\\\m = 5\\\\

Therefore,


(6^(n+2)-6^(n))/(6^(n+1)+6^(n))=5\\\\

User Raugfer
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