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Choose the correct slant asymptote for the function, y=x^2-5x-6/x-6

User Modi
by
7.3k points

2 Answers

5 votes

Answer:

To find the slant asymptote of the function y = (x^2 - 5x - 6)/(x - 6), we need to perform long division to divide the numerator by the denominator.

Dividing x^2 - 5x - 6 by x - 6, we get:

x + 1

___________

x - 6 | x^2 - 5x - 6

- (x^2 - 6x)

___________

x - 6x - 6

- (x - 6)

___________

1

The result of the long division is x + 1 with a remainder of 1.

Therefore, the correct slant asymptote for the function y = (x^2 - 5x - 6)/(x - 6) is:

y = x + 1

User Parag Bhayani
by
7.3k points
0 votes

Answer:

y = x + 1

Explanation:

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