Question

What is the solution set of the quadratic inequality x2 + x-2>/0?

Ax
B XS-1 or X2
C{x\ x2-2 or x 1}
D {x| x2-1 or x<2

Answer 1

Its A, x≤-2 or x1

Explanation:

Edge 2020

Answer 2

solving the inequality:
`x^2+x-2\geq 0` we get
`\x\leq -2 \ or \ x\geq 1\\\`

Option A is correct option

Explanation:

We need to solve the inequality:
`x^2+x-2\geq 0`

We can solve using factors:

`x^2+x-2\geq 0`

We will break the middle term, in such way that their sum is equal to middle term and product is equal to product of first and last term.

`x^2+x-2\geq 0\\x^2+2x-x-2\geq 0\\x(x+2)-1(x+2)\geq 0\\(x-1)(x+2)\geq 0\\x-1\geq 0 \ or \ x+2\geq 0\\x\geq1 \ or \ x\leq-2\\`

So, solving the inequality:
`x^2+x-2\geq 0` we get
`\x\leq -2 \ or \ x\geq 1\\\`

Option A is correct option