Answer:
None of the following statements have the same result.
Explanation:
1) f(2) when f(x) = 3x + 4
We just have to put x=2

So, f(2) when f(x) = 3x + 4 is x=10
2) f⁻¹ (4) when f(x) =3x-4/5
We need to find f⁻¹(x) first.
Put

Now solve for x
Add 4/5 on both sides

Now put f⁻¹(x) instead of x and replace y with x

Now finding f⁻¹(4)

f⁻¹ (4) when f(x) =3x-4/5 is 24/15
3)

Solving:

Solving 3y − 6 = y + 10, we get y=8
None of the following statements have the same result.