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Find the equation of the line shown

Find the equation of the line shown-example-1
User Sufian
by
7.5k points

2 Answers

4 votes

The equation of the line passing through the given points is y =
(1)/(2)x \).

To find the equation of the line passing through the given points, we can use the slope-intercept form of a linear equation:


\[ y = mx + b \]

where m is the slope and b is the y-intercept.

First, calculate the slope m using two of the given points, for example, (2,1) and (10,5):


\[ m = \frac{{\text{{change in }} y}}{{\text{{change in }} x}} \]


\[ m = \frac{{5 - 1}}{{10 - 2}} = (4)/(8) = (1)/(2) \]

Now that we have the slope
(\( (1)/(2) \)), we can use it in the slope-intercept form and substitute one of the points to find the y-intercept b.

Let's use the point (2,1):


\[ 1 = (1)/(2)(2) + b \]

Solve for b:


\[ 1 = 1 + b \]


\[ b = 0 \]

Now we have the slope
(\( (1)/(2) \)) and the y-intercept 0, so the equation of the line is:


\[ y = (1)/(2)x \]

Therefore, the equation of the line passing through the given points is y =
(1)/(2)x \).

User Mahmoud Samir
by
8.4k points
3 votes
i guess it would be 1/2
User Manisha Srivastava
by
7.7k points

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