Question

Find the pOH of a solution made by dissolving 10.4g of HCl in a 500mL solution of water

Answer 1

The pOH of a solution : 13.756

Further explanation

Mass HCl=10.4 g

mol HCl (MW=36.5 g/mol) :

`\tt mol=(mass)/(MW)=(10.4)/(36.5)=0.285`

Volume of HCl = 500 ml = 0.5 L

`\tt M=(n)/(V)\\\\M=(0.285)/(0.5)=0.57~M`

HCl ⇒ H⁺ + Cl⁻

[H⁺]=[HCl]=0.57 M

pH= - log[H⁺]

pH=-log[0.57]=0.244

pH+pOH=14

pOH=14-0.244

pOH=13.756