Answer:
The answer is below
Explanation:
Don has four different chicken coops on his farm. He gathers eggs from each coop every day to sell at the local farmer's market each week. During one week in the summer, the production levels from the coops were compared. • The number of eggs from coop B can be found by subtracting 10 from coop A's production, and then multiplying this result by two-fifths. • The number of eggs from coop C can be found by adding 3 to coop A's production, multiplying this amount by 3, subtracting 4 from this total, and then dividing the whole result by 4. • The number of eggs from coop D can be found by adding 7 to coop A's production, doubling this amount and then dividing the result by 3. A. Define a variable for the number of eggs produced by coop A. Then write expressions for the number of eggs produced by the other coops. B. If coop A produced 125 eggs, how many did each of the other coops produce? C. If the sum of the number of eggs from coop B and coop C was 24 more than the number from coop D. How many eggs did each coop produce
Solution:
a) Let the number of eggs from coop A be w, number of eggs from coop B be x, number of eggs from coop C be y and number of eggs from coop D be z.
x = 2/5(w - 10) (1)
y = (3(w + 3) - 4)/4
y = (3w + 5) / 4 (2)
z = 2(w + 7)/3 (3)
b) Given that w = 125 eggs:
x = 2/5(125 - 10) = 46 eggs
y = (3(125) + 5) / 4 = 95 eggs
z = 2(125 + 7)/3 = 88 eggs
c) x + y = z + 24.
i.e. 2/5(w - 10) + (3w + 5)/ 4 = 2(w + 7)/3 + 24
multiply through by 60:
24w - 240 + 45w + 75 = 40w + 280 + 1440
69w - 165 = 40w + 1580
29w = 1885
w = 65 eggs
x = 2/5(65 - 10) = 22 eggs
y = (3(65) + 5) / 4 = 50 eggs
z = 2(65 + 7)/3 = 48 eggs