Question

6 pounds of apples and 3 pounds of oranges cost 24 dollars.5 pounds of apples and 4 pounds of oranges cost 23 dollars. Set up a system of equations and solve to find out the cost for each pound of apples and each pound of oranges.

Answer 1

Answer:cost of each pound of apple= $3

And cost of each pound of orange =$2

Explanation:

Step 1

Let cost of apples = x

And cost of Oranges =y

Let 6 pounds of apples and 3 pounds of oranges cost 24 dollars be represented as

6 x + 3y= 24----- equation 1

Also, Let 5 pounds of apples and 4 pounds of oranges cost 23 dollars be represented as

5x+ 4y= 23----- equation 2

Step 2

6 x + 3y= 24----- equation 1

5x+ 4y= 23----- equation 2

Using substitution method to solve the equation

6 x + 3y= 24

24-6x=3y

y= 24-6x/3 = 8-2x

Y= 8-2x

Substituting the value of y= 8-2x into equation 2

5x+ 4( 8-2x)= 23

5x+ 32 -8x= 23

32-23= 8x-5x

9=3x

x=9/3

x=3

Putting the value of x= 3 in equation 1 and solving to find y

6 x + 3y= 24

6(3) +3y= 24

18+3y=24

3y= 24-18

3y=6

y=6/3= 2

Therefore the cost of each pound of apple= $3

And cost of each pound of orange =$2