Question

For students majoring in Hospitality Management, it was determined that 5% have visited 1–10 states, 16% have visited 11–20 states, 45% have visited 21–30 states, 19% have visited 31–40 states, and 15% have visited 41–50 states. Suppose a Hospitality Management student is randomly picked. What is the probability that the student has visited 30 or fewer states?

Answer 1

.55

Explanation:

just subtract .45 from 1 and then you have your answer.

Answer 2

9514 1404 393

Answer:

66%

Explanation:

The categories are mutually exclusive, so we have ...

P(≤30) = P(1–10) +P(10–20) +P(20–30) = 5% +16% +45%

P(≤30) = 66%

The probability is 66% that a randomly chosen student has visited 30 or fewer states.