227k views
4 votes
If an object has a weight of 4050 N near the surface of the Earth, what is its mass?

User Ryan Tate
by
7.8k points

1 Answer

2 votes

Answer:

417.5 kg

Step-by-step explanation:

Since the gravitational for of attraction F, equals the weight of the object W when its close to the earth, F = GMm/R² = W = mg where m = mass of object and g = acceleration due to gravity close to the earth = 9.8 m/s².

g = GM/R² where g = acceleration due to gravity close to the earth, G = universal gravitational constant = 6.67 × 10⁻¹¹ Nm²/kg², M = mass of earth = 5.927 × 10²⁴ kg and R = radius of earth = 6.4 × 10⁶ m

So, g = GM/R²

= 6.67 × 10⁻¹¹ Nm²/kg² × 5.927 × 10²⁴ kg/(6.4 × 10⁶ m)²

= 39.53 × 10¹³ Nm²/kg ÷ 40.96 × 10¹² m²

= 9.65 N/kg

≅ 9.7 N/kg

= 9.7 m/s²

Since W = 4050 N and W = mg

m = W/g = 4050 N/9.7 m/s²

= 417.53 kg

≅ 417.5 kg

So, the mass of the object is 417.5 kg

User Erik Bender
by
7.8k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.