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What is the slope of the line that passes through the pair of points (1/3, -1) and ( -2, 9/2)​

User Nguyenq
by
7.9k points

2 Answers

4 votes

Answer:

bsbsh

Explanation:

u2uwj wwjwj ejwnw ejwnw ejwjw ejwbe ejeje eje eje eeje ehe eje ejw ehe ejwbehe ejw ejw ejw ehe ebe e

User XeniaSis
by
8.1k points
4 votes

Answer:


\boxed{m = - (33)/(14) }

.

Explanation:

Use the form below


\boxed{\boxed{m = (y_2 - y_1)/(x_2 - x_1) }}

Where


  • m is a slope

  • (x_1,~y_1) and
    (x_2,~y_2) are the point of the line

.

So, the slope is


((1)/(3) ,~ -1) \to x_1 = (1)/(3) ~and~y_1 = -1


(-2,~ (9)/(2) ) \to x_2 = -2~and~y_2 = (9)/(2)

.


m = ((9)/(2) -(-1))/(-2-(1)/(3) )


m = ((11)/(2) )/((-7)/(3) )


m = (11)/(2) / (-(7)/(3) )


m = (11)/(2) * (-(3)/(7) )


m = - (33)/(14)

.

Happy to help:)

User Theycallhimart
by
8.3k points

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