Question

Question 3 of 10
What is the slope of the line that contains the points (-1, 2) and (4, 3)?

Answer 1

1/5 units

Explanation:

Given co-ordinates:

(-1, 2) and (4, 3)

Solution:

Use slope formulae:

`m = \rm\cfrac{y_2-y_1}{x_2-x_1}`

ATP,

• 
  `(y_2,y_1) = (3,2)`
• 
  `(x_2,x_1) =( 4 ,- 1)`

Substituting them on the formula,we obtain

• 
  `m = \cfrac{3 - 2}{4 - ( - 1)}`
• 
  `m = \cfrac{1}{4 + 1}`

• 
  `m = \boxed{\rm \cfrac{1}{5} \: units}`

Hence the slope of the line is 1/5 units.

Answer 2

1/5

Explanation:

We can use the slope formula

m = ( y2-y1)/(x2-x1)

where (x1,y1) and (x2,y2) are points on the line

m = ( 3-2)/(4 - -1)

= (3-2)/(4+1)

= 1/5