Answer:
The final volume, occupied by the gas at 20° C (293.15 K) and 5.60 atm, is approximately 27.65 L
Step-by-step explanation:
The given parameters are;
The initial volume, V₁ = 35.0 L
The initial temperature, T₁ = 25 °C = 298.15 K
The initial pressure, P₁ = 4.50 atm
The final volume, V₂ = Required
The final temperature, T₂ = 20 °C = 293.15 K
The final pressure, P₂ = 5.60 atm
From the combined gas equation, we have;
P₁·V₁/T₁ = P₂·V₂/T₂
∴ V₂ = (P₁·V₁/T₁) × T₂/P₂
By substituting the known values, we get;
V₂ = (4.50 × 35.0/298.15) × 293.15/5.60 ≈ 27.65
Therefore, the final volume, occupied by the gas at 20° C (293.15 K) and 5.60 atm, V₂ ≈ 27.65 L