Answer:
151200
Explanation:
We want to know how many permutations of 6 digits can be chosen from 10 different digits, so we use the formula:
nPr=n!(n−r)!
Here, r=6 and n=10, so we have:
10P6=10!(10−6)!=10!4!=10⋅9⋅8⋅7⋅6⋅5⋅4!4!=151,200
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