Question

In rhombus ABCD, diagonal BD= 6" and diagonal AC-8".
The sides of the rhombus are

Answer 1

Answer: 5

Explanation:

Let the point where the diagonals intersect be point E.

Since the diagonals of a rhombus are perpendicular bisectors of each other, this means that:

• BE = 3
• AE = 4
• AEB is a right triangle

So, using the Pythagorean theorem,

`3^(2)+4^(2)=(AB)^(2)\\\\25=(AB)^(2)\\\\AB=5`

So, each side of the rhombus has a length of 5.