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If I have 5 mole of a gas at a pressure of 7.6 atm and a volume of 11 liters, what is the temperature?

1 Answer

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Answer:

203.75 K

Step-by-step explanation:

use the ideal gas law equation: PV=nRT, R being the constant 0.08206 L-atm/mol-K.

plug in the values given:

(7.6 atm) (11.0 L) = (5.0 mol) (0.08206 L-atm/mol-K) (T)

and solve for T!

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