Question

The volume of water in a graduated cylinder was increased from 52.0 mL to 75.5 mL when a piece of irregular metal was placed in the water. If the piece of metal has a mass of 265.6 g, what is the density of the metal?

Answer 1

Approximately 11.3 g/mL

Step-by-step explanation:

The formula for density is mass divided by density. In this problem, the mass is already given: 265.6 grams. The density is the part with the milliliters. 75.5 mL - 52.0 mL is 23.5 mL.

After plugging these numbers into the formula, you get 265.6 g/23.5 mL. After divided those numbers, you get 11.30212..... g/mL, which rounds to 11.30 g/mL.

I hope this helps!

Answer 2

11.30 g/mL

Step-by-step explanation:

The density of a substance can be found by using the formula

`density = (mass)/(volume) \\`

volume = final volume of water - initial volume of water

volume = 75.5 - 52 = 23.5

From the question we have

`density = (265.6)/(23.5) \\ = 11.302127...`

We have the final answer as

11.30 g/mL

Hope this helps you