Answer:
f(x) is positive for all x > 10
Explanation:
Given function:
![f(x)=(10)/(x^2-7x-30)](https://img.qammunity.org/2023/formulas/mathematics/high-school/12ak8eguy6msfdeumut0h0bfnk1fbgp2kq.png)
Asymptote
Asymptote: a line which the curve gets infinitely close to, but never touches.
Factor the denominator of the function to find the vertical asymptotes:
![\implies x^2-7x-30](https://img.qammunity.org/2023/formulas/mathematics/high-school/ifb4t7px1bkkmq0i182hh6yb43nxffeymc.png)
![\implies x^2-10x+3x-30](https://img.qammunity.org/2023/formulas/mathematics/high-school/tzs2v52iommfrisaktljjpltj8c27ulhvm.png)
![\implies x(x-10)+3(x-10)](https://img.qammunity.org/2023/formulas/mathematics/high-school/kei4sprgnrjr6fw1ooxncjd58ilnyzdeiv.png)
![\implies (x+3)(x-10)](https://img.qammunity.org/2023/formulas/mathematics/high-school/8r9o3fhq2bhfjlw0ak1huxeobmiu1j5u7l.png)
Therefore:
![f(x)=(10)/((x+3)(x-10))](https://img.qammunity.org/2023/formulas/mathematics/high-school/9n75mjo8l4sylr9i5cu61m26h5742bzpmb.png)
The function is undefined when the denominator is equal to zero.
Therefore, there are vertical asymptotes at x = -3 and x = 10
and a horizontal asymptote at y = 0
f(x) is positive for (10, ∞)
f(x) is negative for (-3, 10)
f(x) is positive for (-∞, -3)