Question

PLEASE I NEED HELP RN!!!

Find the Incenter: Given A (-4,2), B(4,5), and C(3,-1) Rounded to the nearest hundredth.

Answer 1

9514 1404 393

Answer:

(1.43, 1.87)

Explanation:

The formula for the incenter requires we know the lengths of the sides of the triangle. These are found using the distance formula.

BC = √((4-3)^2 +(5+1)^2) = √37

AC = √((-4-3)^2 +(2+1)^2) = √58

AB = √((-4-4)^2 +(2-5)^2) = √73

Then the incenter is ...

(A(BC) +B(AC) +C(AB))/(BC +AC +AB)

≈ (6.08276(-4, 2) +7.61577(4, 5) +8.54400(3, -1))/22.2425

≈ (1.42808, 1.87480)

Rounded to hundredths, the incenter is (1.43, 1.87).