Question

How many atoms are in 18.99g of fluorine?

Answer 1

18.99g/mol F = 1 mole of F

1 mole is equal to Avogadro's number which is:

`6.02214076 × {10}^(23)`

Therefore, one mole of fluorine has 6.02214076 × 10^23 fluorine atoms.

Answer 2

Step-by-step explanation:

The Molar mass of fluorine= 18.99

Moles=mass/molar mass=18.99/18.99=1

Numbers of atoms=1x6.02x10^23=6.02x10^23

I hope it helps