Question

6. How many aluminum atoms are there in 3.50 grams of Al₂O3?

Answer 1

4.13×10^22 atoms

Step-by-step explanation:

1. Find number of moles

mole=mass/rmm of compound

mole= 3.50/102

mole= 7/204 mol

2. Multiply it with avagadros constant( 6.02×10^23 particles)

7/204 × 6.02×10^23= 2.0657×10^22

3. Multiply it with the number of ALMINIUM ATOMS IN AL203( which is 2 atoms)

2.0657×10^22 × 2

you get 4.13×10^22 atoms