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If a(2x-3) = bx+5 then the solution for x in terms of a and b is

2 Answers

3 votes

Answer:

x=(3a+5)/(2a-b)

Explanation:

We spread the a to the 2x and -3 first,

2ax -3a= bx+5 5ax

By adding 3a, we pass the -3a over

2ax=bx+5+3aa bx+5+3aa

We'll pass the bx over the bx, then

2ax-bx=5+3aa-bx=5

Now we will party like this on the left side,

5+3a) x(2a-b)=5+3a)

Everything we have to do to find x is to separate both sides by (2a-b)

x=(3a+5)/=(3a+5)/ (2a-b)

User Labago
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4.6k points
0 votes

Answer:

x = (5 + 3a)/(2a - b)

General Formulas and Concepts:

Pre-Algebra

  • Equality Properties

Explanation:

Step 1: Define equation

a(2x - 3) = bx + 5

Step 2: Solve for x

  1. Distribute a: 2xa - 3a = bx + 5
  2. Add 3a on both sides: 2xa = bx + 5 + 3a
  3. Subtract bx on both sides: 2xa - bx = 5 + 3a
  4. Factor out x: x(2a - b) = 5 + 3a
  5. Isolate x: x = (5 + 3a)/(2a - b)
User Thibaud Colas
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