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19 votes
19 votes
The perimeter of a quadrant of a circle is 71.4cm. Find its area ​

User Darren Joy
by
2.5k points

2 Answers

24 votes
24 votes

Answer:

circle: 6490.9 cm², quadrant: 1622.7 cm²

Explanation:

The circumference of the entire circle is known as 2πr and it is 4 times the given value, since a circle has 4 quadrants:

2πr = 4·71.4 = 285.6, so r = 285.6 / 2π ≈ 45.45

The area of a circle is πr², filling in the value for r we just found:

πr² = π 45.45² ≈ 6490.9 cm²

So the area of a quadrant is one fourth of that:

6490.9/4 = 1622.7 cm²

The question about "its area" can denote the entire circle, or just the quadrant, so two answers are provided.

User Ragnarius
by
2.7k points
26 votes
26 votes

Answer:

Area = 1256 cm²

Explanation:


\textsf{Perimeter of a quadrant of a circle}=\left((\pi)/(2)+2\right)r


\textsf{(where r is the radius)}

Given:

  • Perimeter = 71.4 cm
  • π = 3.14

Substitute the given value into the equation and solve for r:


\implies 71.4=\left((3.14)/(2)+2\right)r


\implies 71.4=3.57r


\implies r=(71.4)/(3.57)


\implies r=20

Therefore, the radius of the circle is 20 cm


\textsf{Area of a circle}=\pi r^2 \quad \textsf{(where r is the radius)}

Substituting the found value of r into the equation and solving for A:


\implies A=3.14(20)^2


\implies A=1256

Therefore, the area of the circle is 1256 cm²

User Soroush Khosravi
by
3.2k points