Question

Help needed :


`\quad \sf \: {x}^(2) = 1 - 37`

solve for x ​

Answer 1

• x = 6i, -6i

Step-by-step explanation:

`\sf x^2=1-37`

Subtract 37 from 1 = -36

`\boxed{\sf x^2=? :\: x=√(?),\:\:-√(?)}`

`\sf x=√(-36)`

`\sf x=-√(-36)`

Apply Radical Rule:-

`\boxed{ \sf √(-a)=√(-1)√(a)}`

`\sf √(-36)=√(-1)√(36)`

`\sf √(-1)√(36)`

`\boxed{\sf √(-1 )=i}`

`\sf √(36)i`

`\sf 6i`

___________

`\sf x=-√(-36)`

`\sf -√(-36)`

`\sf -6i`

Therefore, x = 6i, -6i.

__________________________

Answer 2

x = 6i, -6i

Step-by-step explanation:

x² = 1 - 37 (subtract)

x² = -36 (square root both sides)

x = ±√-36 (breakdown)

x = +√-36, -√-36 (simplify)

x = 6i, -6i