Answer:
V = 48.64 L
Step-by-step explanation:
Given data:
Mass of CO₂ = 85.63 g
Temperature = 273 K
Pressure = 1 atm
Volume of CO₂ = ?
Solution:
Number of moles of CO₂:
Number of moles = mass/molar mass
Number of moles = 85.63 g / 40 g/mol
Number of moles = 2.14 mol
Volume in Litter:
PV = nRT
R = general gas constant = 0.0821 atm.L/mol.K
1 atm× V = 2.14 mol ×0.0821 atm.L/mol.K ×273 K
V = 48.64 atm.L / 1 atm
V = 48.64 L