Answer:
Part A
One method for solving a system of equations is solving by substitution.
Substitute the variable in one equation with the expression of the variable in the other equation.
Replace the y of "y = 2x - 2" with "y = 4x" to make "4x = 2x - 2".
Part B
![\large\begin{array} c \cline{1-3} x & 4x & 2x-2 \\\cline{1-3} 3 & 12 & 4\\\cline{1-3} 2 & 8 & 2\\\cline{1-3} 1 & 4 & 0\\\cline{1-3} 0 & 0 & -2\\\cline{1-3} -1 & -4 & -4\\\cline{1-3} -2 & -8 & -6\\\cline{1-3} -3 & -12 & -8\\\cline{1-3} \end{array}](https://img.qammunity.org/2023/formulas/mathematics/college/kx8ci5h85bxiriyg9qza36qx40m37zjgdk.png)
The only integer for which both equations give the same result is x = -1.
Therefore, the solution is x = -1
Part C
To solve the equation graphically, graph the lines y = 4x and y = 2x - 2.
The x-coordinate of the point of intersection is the solution to the equation 4x = 2x - 2
(see attached)