Write the equation of the line passing through points (-1,0) and perpendicular to the line y=1/3x-7

Question

asked Mar 28, 2021 227k views

1 Answer

Lexeme · Answer 1 · 2021-04-03T04:11:39+0000

Answer:

Using the point-slope form of the equation, the equation of the line passing through (-1,0) and perpendicular to the line is:

y=-3x-3

Explanation:

We know the slope-intercept of line equation is

y=mx+b

where m is the slope, and b is the y-intercept

Given the line

$y=\:(1)/(3)x-7$

Thus, the slope of the line is:

m=1/3

As we know that the slope of the perpendicular line is basically the negative reciprocal of the slope of the line, so

The slope of the perpendicular line will be: -3

Therefore, using the point-slope form of the equation, the equation of the line passing through (-1,0) and perpendicular to the line is:

$y-y_1=m\left(x-x_1\right)$

$y-0=-3\left(x-\left(-1\right)\right)$

$y=-3\left(x+1\right)$

y=-3x-3