Question

Write the equation of the line passing through points ( -2,-5) and (1,1)

Answer 1

The equation of the line is:

`y=2x-1`

Explanation:

Given the points

• (-2, -5)

• (1, 1)

Finding the slope between the points

`\mathrm{Slope}=(y_2-y_1)/(x_2-x_1)`

`\left(x_1,\:y_1\right)=\left(-2,\:-5\right),\:\left(x_2,\:y_2\right)=\left(1,\:1\right)`

`m=(1-\left(-5\right))/(1-\left(-2\right))`

`m=2`

We know the slope-intercept form of the line equation

`y=mx+b`

where m is the slope and b is the slope-intercept form

substituting the value m=2 and the point (-2, -5) to find the b-intercept

`y=mx+b`

-5 = 2(-2) + b

b = -5+4

b = -1

Now, substituting m=2 and b=-1 in the slope-intercept form to get the equation of a line

y=mx+b

y=2x+(-1)

y=2x-1

Thus, the equation of the line is:

`y=2x-1`