Question

What is the equation of the line that passes through the point (-1, -5) and has a
slope of -12

Answer 1

Thus, the equation of a line is: y = -12x-17

Step-by-step explanation:

• point = (-1, -5)

• slope = -12

Using the point-slope form

`y-y_1=m\left(x-x_1\right)`

where m is the slope, and (x₁, y₁) is the point

substituting the values m = -12 and the point (-1, -5)

`y-y_1=m\left(x-x_1\right)`

y-(-5) = -12(x-(-1))

y+5 = -12 (x+1)

y+5 = -12x-12

y = -12x-12-5

y = -12x-17

Thus, the equation of line is: y = -12x-17