Question

Consider the following functions.

f(x)=2x^2+4x+10
g(x)=3x-11
h(x)=3x^3+x^2=21
The value of h(f(g(2)))

Answer 1

Explanation:

h(f(g(2)))=

h(f(3*2-11))) = h(f( -5))=

h((2*(-5)^2) +4*(-5) +10) = h (50 -20 +10) = h(40)

now calculate h(40) but check if you wrote corectly the equation