Question

A solution has [H+] = 2.35 × 10-3 M. Find the [OH-] for this solution

Answer 1

[OH-] for this solution is 4.255*10^-12

Step-by-step explanation:

We are given

[H+] = 2.35 × 10-3 M

we need to find the concentration of [OH-]

we know from Equilibrium

[H+][OH-] = 10^-14

[OH-] = 10^14/2.35*10^10^-3

[OH-] = 0.4255*10^-11

[OH] = 4.255*10^-12

Therefore the Concentration of [OH-] for this solution is 4.255*10^-12