Question

Consider the following functions.

F(x)= 2x^2+4x+10
G(x)= 3x-11
H(x)= 3x^2+x^2-21

The value of H(F(-2)) is

Answer 1

The value of H(F(-2)) is 379

Explanation:

Soln,

Given,

F(x)= 2x^2+4x+10

G(x)= 3x-11

H(x)= 3x^2+x^2-21

Now,

F(-2) = 2(-2)^2 + 4×(-2) + 10

= 2×4 + (-8) + 10

= 8-8+10

= 18 - 8

= 10

Again,

H(F(-2)) = 3x^2 + x^2 - 21

Putting the value of F(-2) , we get

H(10) = 3×10^2 + 10^2 - 21

= 3×100 + 100 - 21

= 300 + 100 - 21

= 400 - 21

= 379

Therefore, H(F(-2)) = 379.