Question

A batter hits a ball at 25 m/a 37 degrees above the horizon. (Part A) how long is the ball in the air? (Part b) how far does it travel?

Answer 1

Step-by-step explanation:

we know

v=u-gt

At max height v=0

uy=usin30

now,25sin37=gt

15.07/9.8=t

t=1.53s to reach max height now to come on ground it takes same time

so time taken t=3.07s

We know ,range=ucos37×t

=25cos37×3.07

max distance=61.3meter