Answer:
Each ammeter in the loops would read 4A and if other loop is added the loop ammeter would read 3A
Step-by-step explanation:
The formula for current in parallel is;
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The total current value from the source battery is 12A, so the three loops with no load would read;
= 12 / 3 = 4A
When another loop is added to the circuit, the total current would be divided by the four loop which will give a value of 3A for each loop.