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Use the substitution method to solve each linear system. 4x - 3y = -13,-2x + y = 4

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Answer:

The solutions to the system of equations are:


x=(1)/(2),\:y=5

Explanation:

Given the system of the equations


\begin{bmatrix}4x-3y=-13\\ -2x+y=4\end{bmatrix}

Isolate x for for 4x-3y=-13


4x-3y=-13


4x=-13+3y

Divide both sides by 4


x=(-13+3y)/(4)

substitute y=5


x=(-13+3\cdot \:5)/(4)


x=(1)/(2)

The solutions to the system of equations are:


x=(1)/(2),\:y=5

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