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What is the displacement from a starting position of (14.0, 3.0) m to a final position of (−3.0, −4.0) m?

User Mike Brind
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1 Answer

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Answer:

change in y = -7

change in x = -17

magnitude of displacement = sqrt(7^2+17^2)

tan of angle below -x axis = 7/17

because in third quadrant where x and y are negative

User Cuca
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