Question

prove that for any natural value of n the value of the expression (n+2)^2-(n-2)^2 is a multiple of 8.

Answer 1

5866 is the answer to this

Answer 2

Se below

Explanation:

Simplifying, using formula a^2 - b^2 = (a +b)(a - b)

• (n + 2)^2 - (n - 2)^2 =
• (n + 2 + n - 2)(n + 2 - n + 2) =
• 2n(4) =
• 8n

As we see the resulting expression is multiple of 8