Explanation:
11^(8x) = 4
we need a logarithm to solve for variables in an exponent.
in this case we start with the logarithm to the base of 11 :
8x = log11(4)
x = log11(4)/8
how can we get log11 ?
remember,
loga(b) = logc(b)/logc(a)
and so,
x = (log10(4)/log10(11)) / 8 = 0.072266207... ≈ 0.07