Question

Find the solution to the following system of equations write as an ordered pair

3x +y= 20
x +y = 12

Answer 1

Answer: (4,8)

First you have to solve for Y in either equation. I solved for Y in the second equation and my new equation was y=12-x.

Then you plug this new equation into the equation you did not touch. It will become 3x+ (12-x)=20.

Next you solve this equation for X which would be 4.

Lastly you plug in 4 in either equation. I plugged it in the first equation and it became 3(4)+y=20

I hope this helps some :)